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Confidence Interval for a Proportion — FRQ Walkthrough

A free-response question in exam style, fully worked — then the scoring logic behind every point.

The question · original, exam-style

A regional library wants to estimate the proportion of its cardholders who used the e-book service at least once in the past month. Staff take a random sample of 180 cardholders and find that 63 of them used the e-book service in that window. Construct and interpret a 95% confidence interval for the true proportion of all cardholders who used the e-book service at least once in the past month.

Written by Marlio as an analog of the exam format. Not a College Board question.

Model response

Identify: One-sample z-interval for a proportion. p̂ = 63/180 = 0.35.

Conditions: Random — the 180 cardholders are stated to be a random sample. 10% — 180 is less than 10% of all cardholders. Large counts — n·p̂ = 63 ≥ 10 and n(1 − p̂) = 117 ≥ 10. Conditions met.

Calculate: For 95% confidence, z* = 1.96. The standard error is √(0.35·0.65/180) = √0.001264 ≈ 0.0356, so the margin of error is 1.96·0.0356 ≈ 0.070. The interval is 0.35 ± 0.070 = (0.280, 0.420).

Interpret: We are 95% confident that the true proportion of all library cardholders who used the e-book service at least once in the past month is between 0.280 and 0.420.

How it’s scored — point by point

  1. POINT 1

    Identifies the procedure and checks the conditions.

    Name the one-sample z-interval for a proportion and verify random, 10%, and large counts with the actual counts 63 and 117. This is the point most often lost, by skipping the large-counts check.

  2. POINT 2

    Correct mechanics: critical value, standard error, and interval.

    Uses z* = 1.96 for 95%, builds the standard error from p̂, and reports the interval (0.280, 0.420). A wrong critical value (for example 1.645) or a standard error built from a wrong p̂ loses this point.

  3. POINT 3

    Interprets the interval in context.

    The interpretation must be about the true population proportion of cardholders, use the phrase "95% confident," and give the endpoints in context. Interpreting it as a probability about one interval, or describing 95% of cardholders, earns no credit.

Common point-losers

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